I NEED HELP WITH THIS BY TONIGHT. I do not understand this at all.


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I NEED HELP WITH THIS BY TONIGHT. I do not understand this at all. ATTACHMENT PREVIEW Download attachment homework help.docx 1. Use the permanent marker to label the two 100 mL beakers as “1” and “2”. 2. Pour 50 of the blue beads and 50 of the yellow beads into Beaker 1. Sift or stir the beads around to create a homogenous mixture. 3. Pour 50 of the red beads and 50 of the green beads into Beaker 2. Sift or stir the beads around to create a homogenous mixture. Assumptions for the remainder of the experiment: Beaker 1 contains beads that are either yellow or blue. Beaker 2 contains beads that are either green or red. Both beakers contain approximately the same number of each colored bead. These colors correspond to the following traits (remember that Y/y is for kernel color and S/s is for smooth/wrinkled): 1. Yellow (Y) vs. Blue (y) 2. Green (G) vs. Red (g). Part 2: Monohybrid Cross 1. Randomly (without looking) take two beads out of Beaker 1. This is the genotype of Individual #1. Record the genotype in Table 1. Do not put these beads back into the beaker. Table 1: Parent Genotypes: Monohybrid Crosses Generation Genotype of Individual 1 Genotype of Individual 2 P P1 P2 P3 P4 2. Repeat Step 1 for Individual #2. These two genotypes represent the parents (generation P) for the next generation. 3. Set up a Punnett square and determine the genotypes and phenotypes for this cross. Record your data in Table 2 4. Repeat Step 3 four more times (for a total of five subsequent generations). Return the beads to their respective beakers when finished. Table 2: Generation Data Produced by Monohybrid Crosses Parents P P1 P2 P3 P4 Possible Offspring Genotypes Possible Offspring Phenotypes Genotype Ratio Phenotype Ratio Read more

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