9. One mole of water at the initial conditions of…


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9. One mole of water at the initial conditions of 0.0◦C and 1atm of pressure is turned to steam (final conditions 100C and 1atm of pressure) by the following two paths. Do you expect ∆S for each path will be the same or different and why? Calculate ∆S for each step along each path assuming the heat capacity for water and steam is constant, 75.48J/K mol and 35.54 J/K mol respectively. Calculate the total ∆S for each path. a. Path a i. the water is heated at constant P =1 atm to 100◦C ii. allowed to boil to steam (∆vapH◦=40.67 kJ/mol at this temperature) b. Path b i. The pressure is lowered to 0.006 atm (to calculate ∆S for this step this you need the value for α which is 0.000214/K for water) ii. the water evaporates to steam at 0.0◦C (∆vapH◦=44.92 kJ/mol at this temperature) iii. The steam is heated to 100◦C at a constant pressure of 0.006atm iv. The steam is compressed to 1atm at constant temperature of 100◦C

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